document.write( "Question 1004029: a college student earned $8900 during the summer. the student invested part of the money at 9% and the rest at 6% if the student received a total of $654 in intrest at the end of the year, how much was invested at 9% \n" ); document.write( "

Algebra.Com's Answer #620648 by addingup(3677) $\"\"$ $\"About$

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He has invested x money at 9%. And, he has invested the rest, meaning 8,900-x at 6%. In equation form:
\n" ); document.write( ".09x+.06(8,900-x)= 654 Now just do the math:
\n" ); document.write( ".09x+524-.06x= 654
\n" ); document.write( ".03x= 120
\n" ); document.write( "x= 4,000 This is how much he invested at 9%. And:
\n" ); document.write( "8,900-4,000= 4,900 is how much he invested at 6%.
\n" ); document.write( "Proof:
\n" ); document.write( "4,000*.09= 360
\n" ); document.write( "4,900*.06= 294
\n" ); document.write( "_ _ _ _ _ _------
\n" ); document.write( "Total......654 We have the correct answer \n" ); document.write( "

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