document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004071>Question 1004071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 30 inches, and its area is 54 square inches. Find the length of the longest side of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620619 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the facts we have<BR>\n" );
document.write( "P = 2L + 2W = 30 and<BR>\n" );
document.write( "A = LW = 54<BR>\n" );
document.write( "Solve the first for W and substitute into the second one...<BR>\n" );
document.write( "2L + 2W = 30<BR>\n" );
document.write( "L + W = 15<BR>\n" );
document.write( "W = 15 - L<BR>\n" );
document.write( "and then<BR>\n" );
document.write( "L(15 - L) = 54<BR>\n" );
document.write( "-L^2 + 15L - 54 = 0<BR>\n" );
document.write( "or<BR>\n" );
document.write( "L^2 - 15L + 54 = 0<BR>\n" );
document.write( "Factoring we get<BR>\n" );
document.write( "(L - 9)(L - 6) = 0<BR>\n" );
document.write( "L = 9 in<BR>\n" );
document.write( "W = 6 in </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );