document.write( "Question 1003833: a girl arrives at school 10 minutes early .another girl is 3 minutes late .how long has the first girl been at school before the second girl arrives! \n" ); document.write( "
Algebra.Com's Answer #620616 by rosey51235(30)![]() ![]() You can put this solution on YOUR website! 13 minutes. \n" ); document.write( "If girl 1 is 10 minutes early, then in those 10 minutes class starts. \n" ); document.write( "Girl 2 is 3 minutes LATE. So you simply add the amount of lateness to the 10 minutes of earliness. 10+3=13 \n" ); document.write( "Hope I helped :) \n" ); document.write( "-rosey51235 \n" ); document.write( " |