document.write( "Question 85852: How many milliliters of alcohol must be added to 200 milliliters of a 25% iodine solution to make a 10% iodine solution \n" ); document.write( "
Algebra.Com's Answer #62061 by ankor@dixie-net.com(22740)\"\" \"About 
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How many milliliters of alcohol must be added to 200 milliliters of a 25% iodine solution to make a 10% iodine solution:
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\n" ); document.write( "Let x = amt of alcohol required;
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\n" ); document.write( "Think of Alcohol is a 0% iodine solution
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\n" ); document.write( "Final mixture amt = (x+200)
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\n" ); document.write( "Write a a % iodine equation:
\n" ); document.write( ".25(200) + 0(x) = .10(x+200)
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\n" ); document.write( "50 + 0 = .10x + 20
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\n" ); document.write( "50 - 20 = .10x
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\n" ); document.write( "30 = .10x
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\n" ); document.write( "x = 30/.10
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\n" ); document.write( "x = 300 ml of alcohol required to make a 10% iodine solution
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\n" ); document.write( "Check solution:
\n" ); document.write( "the total amt 200 + 300 = 500
\n" ); document.write( ".25(200) = .1(500)
\n" ); document.write( "50 = 50 \n" ); document.write( "
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