document.write( "Question 1004038: The perimeter of a rectangle varies jointly with its length and width. If the perimeter of a rectangle is 24 inches with a length of 5 and a width of 7, what is a rectangle’s width with a perimeter of 32 inches and a length of 5? \n" ); document.write( "
Algebra.Com's Answer #620602 by addingup(3677) You can put this solution on YOUR website! 11 is the width: \n" ); document.write( "Perimeter= 2w+2l, let me turn the problem around: \n" ); document.write( "2w+2l= Perimeter. We know the length is 5 and the perimeter 32: \n" ); document.write( "2w+2(5)= 32 \n" ); document.write( "2w+10= 32 subtract 10 on both sides: \n" ); document.write( "2w= 22 divide both sides by 2 \n" ); document.write( "w= 11 \n" ); document.write( " \n" ); document.write( " |