document.write( "Question 1004038: The perimeter of a rectangle varies jointly with its length and width. If the perimeter of a rectangle is 24 inches with a length of 5 and a width of 7, what is a rectangle’s width with a perimeter of 32 inches and a length of 5? \n" ); document.write( "
Algebra.Com's Answer #620602 by addingup(3677)\"\" \"About 
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11 is the width:
\n" ); document.write( "Perimeter= 2w+2l, let me turn the problem around:
\n" ); document.write( "2w+2l= Perimeter. We know the length is 5 and the perimeter 32:
\n" ); document.write( "2w+2(5)= 32
\n" ); document.write( "2w+10= 32 subtract 10 on both sides:
\n" ); document.write( "2w= 22 divide both sides by 2
\n" ); document.write( "w= 11
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