document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003998>Question 1003998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the accumulated value on an investment of $15,000.00 for 9 years at an interest rate of 11% if the money is compounded <BR>\n" );
document.write( " a) Semi- annually\r<BR>\n" );
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document.write( "b) Quarterly\r<BR>\n" );
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document.write( "c) Monthly \r<BR>\n" );
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document.write( "d) Continuously  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620600 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Po{1+r/t}^nt<BR>\n" );
document.write( "Semi-annually 15000*(1+0.11/2)^18=$39,322.99<BR>\n" );
document.write( "Quarterly 15000(1+(0.11/4))^36=$39,832.46<BR>\n" );
document.write( "Monthly  15000(1+(0.11)/12)^108=$40,186.87<BR>\n" );
document.write( "Continuously 15000e^(0.11*9)=15000e^(0.99)=$40,368.52<BR>\n" );
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