document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004026>Question 1004026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A large corporation would like to estimate the proportion of their employees that have children. The director of human resources takes a random sample of 102 employees and find that 76% of them have children. Calculate a 95% confidence interval for the proportion of all employees at this company that have children (use the traditional formula).\r<BR>\n" );
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document.write( "What is the lower bound of the confidence interval?\r<BR>\n" );
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document.write( "What is the upper bound of the confidence interval? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620594 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a one-sample proportion test<BR>\n" );
document.write( "standard error is sqrt (p)(1-p)/n=<BR>\n" );
document.write( "sqrt (0.76)*(0.24)/102=0.04223<BR>\n" );
document.write( "without rounding, the half CI is 1.96*SE=0.0829<BR>\n" );
document.write( "The whole CI is (0.68,0.84), keeping two decimal places.  One can make it three or four decimal places, but it is already rounded by using 76%, which is not the true number, since 76% of 102=77.52 </SPAN>\n" );
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