document.write( "Question 1004017: Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is necessary, round to the nearest tenth of a degree.
\n" ); document.write( "6sin^2(θ) − 7cos2(θ) = 0
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Algebra.Com's Answer #620579 by fractalier(6550) $\"\"$ $\"About$

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From 6sin^2(θ) − 7cos^2(θ) = 0
\n" ); document.write( "6sin^2(θ) − 7(1 - sin^2(θ) = 0
\n" ); document.write( "13sin^2(θ) − 7 = 0
\n" ); document.write( "13sin^2(θ) = 7
\n" ); document.write( "sin^2(θ) = 7/13
\n" ); document.write( "sin(θ) = +/- sqrt(7/13) = +/- .738
\n" ); document.write( "so that
\n" ); document.write( "θ = 47.2, 132.8, 227.2, 312.8 degrees\r
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