document.write( "Question 85836: the square root of 2x plus three minus the square root ofx plus one equals one \n" ); document.write( "
Algebra.Com's Answer #62052 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the square root of 2x plus three minus the square root ofx plus one equals one \n" ); document.write( ": \n" ); document.write( "Here it is step-by-step, the idea is to perform algebra operations that will get rid of the radicals; Leaving us with a quadratic equation that we solve \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "add \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Square both sides: \n" ); document.write( "2x + 3 = (x+1) + 2*sqrt(x+1) + 1; FOILed [(sqrt(x+1) + 1] * [sqrt(x+1) + 1] \n" ); document.write( ": \n" ); document.write( "2x + 3 = x + 2 + 2*sqrt(x+1) \n" ); document.write( ": \n" ); document.write( "2x - x + 3 - 2 = 2*sqrt(x+1) \n" ); document.write( ": \n" ); document.write( "x + 1 = 2*Sqrt(x+1) \n" ); document.write( ": \n" ); document.write( "Square both sides again: \n" ); document.write( "x^2 + 2x + 1 = 4(x+1); FOILed (x+1)*(x+1) \n" ); document.write( ": \n" ); document.write( "x^2 + 2x + 1 = 4x + 4 \n" ); document.write( ": \n" ); document.write( "x^2 + 2x - 4x + 1 - 4 = 0 \n" ); document.write( ": \n" ); document.write( "x^2 - 2x - 3 = 0 \n" ); document.write( ": \n" ); document.write( "Factors to: \n" ); document.write( "(x - 3)(x + 1 ) = 0 \n" ); document.write( ": \n" ); document.write( "x = +3 \n" ); document.write( "and \n" ); document.write( "x = -1 \n" ); document.write( ": \n" ); document.write( "Check both solutions by substitution in the original equation. \n" ); document.write( " |