document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003897>Question 1003897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that a-3b/a+2b=3, find the value of a+3b/a-2b.  Express your answer as an integer or common or improper fraction reduced to lowest terms.  Do not use decimals.  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620510 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  a-3b/a+2b=3,<BR>\n" );
document.write( "a-3b=3a+6b<BR>\n" );
document.write( "-2a=9b<BR>\n" );
document.write( "a= (-9/2)b<BR>\n" );
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document.write( "(a+3b)/(a-2b)<BR>\n" );
document.write( "(-9b/2) + (6b/2)/(-9b/2)-(4b/2)<BR>\n" );
document.write( "(-3b/2)/(-13b/2)<BR>\n" );
document.write( "3/13<BR>\n" );
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