document.write( "Question 1003814: \r
\n" ); document.write( "\n" ); document.write( "Five years ago,a father was 3 times as old as his son.Now their combined ages amount to 110 years.find the present age of the father.
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Algebra.Com's Answer #620500 by ankor@dixie-net.com(22740)\"\" \"About 
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Five years ago,a father was 3 times as old as his son.
\n" ); document.write( "f - 5 = 3(s - 5)
\n" ); document.write( "f - 5 = 3s - 15
\n" ); document.write( "f = 3s - 15 + 5
\n" ); document.write( "f = 3s - 10
\n" ); document.write( "Now their combined ages amount to 110 years.
\n" ); document.write( "f + s = 110
\n" ); document.write( "Replace f with (3s-10)
\n" ); document.write( "(3s-10 + s = 110
\n" ); document.write( "3s + s = 110 + 10
\n" ); document.write( "4s = 120
\n" ); document.write( "s = 120/4
\n" ); document.write( "s = 30 yrs is the son
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\n" ); document.write( "find the present age of the father. I'll let you do this
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