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document.write( "Five years ago,a father was 3 times as old as his son.Now their combined ages amount to 110 years.find the present age of the father. \n" );
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Algebra.Com's Answer #620500 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Five years ago,a father was 3 times as old as his son. \n" ); document.write( "f - 5 = 3(s - 5) \n" ); document.write( "f - 5 = 3s - 15 \n" ); document.write( "f = 3s - 15 + 5 \n" ); document.write( "f = 3s - 10 \n" ); document.write( "Now their combined ages amount to 110 years. \n" ); document.write( "f + s = 110 \n" ); document.write( "Replace f with (3s-10) \n" ); document.write( "(3s-10 + s = 110 \n" ); document.write( "3s + s = 110 + 10 \n" ); document.write( "4s = 120 \n" ); document.write( "s = 120/4 \n" ); document.write( "s = 30 yrs is the son \n" ); document.write( ": \n" ); document.write( "find the present age of the father. I'll let you do this \n" ); document.write( " |