document.write( "Question 1003885: A solution that is 20% acid and 80% water is mixed with a solution that is 50% acid and 50% water. If twice as much 50% acid solution is used as 20% solution, then what is the ratio of acid to water in the mixture of the solutions? \n" ); document.write( "
Algebra.Com's Answer #620498 by josgarithmetic(39617)\"\" \"About 
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x, how much 20% acid
\n" ); document.write( "y, how much 50% acid
\n" ); document.write( "y/x=2\r
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\n" ); document.write( "\n" ); document.write( "Percent acid of the mixture or solution,
\n" ); document.write( "\"%2820x%2B50y%29%2F%28x%2By%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2820x%2B50%2A2x%29%2F%28x%2B2x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Fx%29%28%2820%2B100%29%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"120%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%2840%29\"-------the percent acid of the new solution.
\n" ); document.write( "This means 40 parts acid, 60 parts water.
\n" ); document.write( "\"40%2F60=highlight%282%2F3%29\"--------the ratio of acid to water.
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