document.write( "Question 1003842: Find the area of the rectangle whose vertices are the points with coordinates (5,2),(5,-6),(0,-6),and (0,2). \n" ); document.write( "
Algebra.Com's Answer #620489 by MathLover1(20849)\"\" \"About 
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the rectangle whose vertices are the points with coordinates:\r
\n" ); document.write( "\n" ); document.write( " (\"5\",\"2\"),(\"5\",\"-6\"),(\"0\",\"-6\"),and (\"0\",\"2\")\r
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\n" ); document.write( "\n" ); document.write( "as you can see, the length of the rectangle is the distance between the points (\"0\",\"2\") and (\"0\",\"-6\")\r
\n" ); document.write( "\n" ); document.write( "and the width is the distance between the points (\"0\",\"2\") and (\"5\",\"2\")\r
\n" ); document.write( "\n" ); document.write( "the length \"L\" is: \r
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Solved by pluggable solver: Distance between two points in two dimensions
The distance (denoted by d) between two points in two dimensions is given by the following formula:
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\n" ); document.write( " \"d=sqrt%28%28x1-x2%29%5E2+%2B+%28y1-y2%29%5E2%29\"
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\n" ); document.write( " Thus in our case, the required distance is
\n" ); document.write( " \"d=sqrt%28%280-0%29%5E2+%2B+%282--6%29%5E2%29=+8+\"
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\n" ); document.write( " For more on this concept, refer to Distance formula.
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\n" ); document.write( "\n" ); document.write( "the width is \"W\":\r
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Solved by pluggable solver: Distance between two points in two dimensions
The distance (denoted by d) between two points in two dimensions is given by the following formula:
\n" ); document.write( "
\n" ); document.write( " \"d=sqrt%28%28x1-x2%29%5E2+%2B+%28y1-y2%29%5E2%29\"
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\n" ); document.write( " Thus in our case, the required distance is
\n" ); document.write( " \"d=sqrt%28%280-5%29%5E2+%2B+%282-2%29%5E2%29=+5+\"
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\n" ); document.write( " For more on this concept, refer to Distance formula.
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\n" ); document.write( "\n" ); document.write( "\"L=8\"
\n" ); document.write( "\"W=5\"\r
\n" ); document.write( "\n" ); document.write( "so, the area is:\"A=LW\"=>\"A=8%2A5\"=>\"A=40\"\r
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