document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003869>Question 1003869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jennifer Chan has just enough money to rent a canoe for 2 1/2 hours. How far out on the lake can she paddle and return if she paddles 3 km/h and back at 2 km/h? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620487 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jennifer Chan has just enough money to rent a canoe for 2 1/2 hours. How far out on the lake can she paddle and return if she paddles 3 km/h and back at 2 km/h? <BR>\n" );
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document.write( "Out DATA:<BR>\n" );
document.write( "rate = 3 km/h ; distance = x km ; time = d/r = x/3 hrs<BR>\n" );
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document.write( "In DATA:<BR>\n" );
document.write( "rate = 2 km/h ; distance = x km ; time = d/r = x/2 hrs<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x/3 + x/2 = 5/2 hrs<BR>\n" );
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document.write( "2x + 3x = 15<BR>\n" );
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document.write( "x = 3 km (distance out)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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