document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003866>Question 1003866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 16. The sum of twice the first number, 4 times the second number, and 5 times the third number is 51. The difference between 5 times the first number and the second number is 35. Find the three numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620482 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 16. The sum of twice the first number, 4 times the second number, and 5 times the third number is 51. The difference between 5 times the first number and the second number is 35. Find the three numbers. <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( " a + b +  c = 16<BR>\n" );
document.write( "2a +4b + 5c = 51<BR>\n" );
document.write( "5a - b + 0  = 35<BR>\n" );
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document.write( "Use any method to find<BR>\n" );
document.write( "a = 8<BR>\n" );
document.write( "b = 5<BR>\n" );
document.write( "c = 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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