document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003856>Question 1003856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please!!!!!!!!!! Help me with this problem. Show all work and steps. Thanks\r<BR>\n" );
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document.write( "1. Find the reduced row echelon form of this augmented matrix\r<BR>\n" );
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document.write( "[ 1  0  0  300<BR>\n" );
document.write( " -3  1  3  400<BR>\n" );
document.write( " -1  0  1  250]\r<BR>\n" );
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document.write( "3. Find the reduced row echelon form of this augmented matrix\r<BR>\n" );
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document.write( "[1  -4  2  200<BR>\n" );
document.write( "-2   9 -4  400<BR>\n" );
document.write( " 1  -4  3  100]\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620471 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20850)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620471\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Row Operation	\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%283%2C4%2C1%2C0%2C0%2C300%2C0%2C1%2C3%2C1300%2C-1%2C0%2C1%2C250%29 ALIGN=MIDDLE  ALT=\"matrix%283%2C4%2C1%2C0%2C0%2C300%2C0%2C1%2C3%2C1300%2C-1%2C0%2C1%2C250%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
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document.write( "1:  add 3 times the 1st row to the 2nd row and you will have\r<BR>\n" );
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document.write( "2: add 1 times the 1st row to the 3rd row and you will have<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%283%2C4%2C1%2C0%2C0%2C300%2C0%2C1%2C3%2C1300%2C0%2C0%2C1%2C550%29 ALIGN=MIDDLE  ALT=\"matrix%283%2C4%2C1%2C0%2C0%2C300%2C0%2C1%2C3%2C1300%2C0%2C0%2C1%2C550%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "3:  add -3 times the 3rd row to the 2nd row and you will have\r<BR>\n" );
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document.write( "and, next one:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%283%2C4%2C1%2C-4%2C2%2C200%2C-2%2C9%2C-4%2C400%2C1%2C-4%2C3%2C100%29 ALIGN=MIDDLE  ALT=\"matrix%283%2C4%2C1%2C-4%2C2%2C200%2C-2%2C9%2C-4%2C400%2C1%2C-4%2C3%2C100%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "add 2 times the 1st row to the 2nd row and you will get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%283%2C4%2C1%2C-4%2C2%2C200%2C0%2C1%2C0%2C800%2C1%2C-4%2C3%2C100%29 ALIGN=MIDDLE  ALT=\"matrix%283%2C4%2C1%2C-4%2C2%2C200%2C0%2C1%2C0%2C800%2C1%2C-4%2C3%2C100%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "add -1 times the 1st row to the 3rd row and you will get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%283%2C4%2C1%2C-4%2C2%2C200%2C0%2C1%2C0%2C800%2C0%2C0%2C1%2C-100%29 ALIGN=MIDDLE  ALT=\"matrix%283%2C4%2C1%2C-4%2C2%2C200%2C0%2C1%2C0%2C800%2C0%2C0%2C1%2C-100%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "add -2 times the 3rd row to the 1st row and you will get\r<BR>\n" );
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document.write( "add 4 times the 2nd row to the 1st row and you will get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%283%2C4%2C1%2C0%2C0%2C3600%2C0%2C1%2C0%2C800%2C0%2C0%2C1%2C-100%29 ALIGN=MIDDLE  ALT=\"matrix%283%2C4%2C1%2C0%2C0%2C3600%2C0%2C1%2C0%2C800%2C0%2C0%2C1%2C-100%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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