document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003851>Question 1003851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a triangle is 30 in. The base of the triangle measures 2in more than twice the height of the triangle. Find the measures of the base and height  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620458 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b=base<BR>\n" );
document.write( "2h=b-2<BR>\n" );
document.write( "h=(b-2)/2<BR>\n" );
document.write( "A=(1/2)bh<BR>\n" );
document.write( "=b*(b-2)/4=30<BR>\n" );
document.write( "(b^2-2b)/4=30<BR>\n" );
document.write( "b^2-2b=120<BR>\n" );
document.write( "b^2-2b-120=0<BR>\n" );
document.write( "(b-12)(b+10)=0<BR>\n" );
document.write( "b=12 in<BR>\n" );
document.write( "h=5 in<BR>\n" );
document.write( "A=(1/2)bh=(1/2)*60=30 in^2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );