document.write( "Question 1003768: What is X in (3x)^(1+ log of X base 3)=3 and how do I get to it? \n" ); document.write( "
Algebra.Com's Answer #620415 by Alan3354(69443)\"\" \"About 
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(3x)^(1+ log of X base 3)=3
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\n" ); document.write( "\"%283x%29%5E%281%2B+log%283%2CX%29%29=3\"
\n" ); document.write( "\"3x%2A%283x%29%5Elog%283%2CX%29%29=3\"
\n" ); document.write( "\"x%2A%283x%29%5Elog%283%2CX%29%29=1\"
\n" ); document.write( "\"x%2A%283%5Elog%283%2CX%29%29%2A%28x%5Elog%283%2Cx%29%29+=+1\"
\n" ); document.write( "\"x%2Ax%2A%28x%5Elog%283%2Cx%29%29+=+1\"
\n" ); document.write( "\"x%5E%28log%283%2Cx%29%29+=+1%2Fx%5E2+=+x%5E-2\"
\n" ); document.write( "\"log%283%2Cx%29+=+-2\"
\n" ); document.write( "\"x+=+3%5E%28-2%29\"
\n" ); document.write( "x = 1/9
\n" ); document.write( "-------------
\n" ); document.write( "Check:
\n" ); document.write( "(1/3)^(1-2) = 3
\n" ); document.write( "It's correct.\r
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