document.write( "Question 1003758: Find the points of intersection, if any, of the pair of curves :
\n" ); document.write( "x^2+y^2=13 , y=x+1
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Algebra.Com's Answer #620410 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "x^2 + y^2 = 13
\n" ); document.write( "y = x + 1
\n" ); document.write( "Substitute (x + 1) for 'y'
\n" ); document.write( "in x^2 + y^2 = 13
\n" ); document.write( "x^2 +(x + 1)^2 = 13
\n" ); document.write( "Multiply out bracket
\n" ); document.write( "x^2 +(x^2 + 2x + 1)= 13
\n" ); document.write( "Remove brackets
\n" ); document.write( "x^2 + x^2 + 2x + 1 = 13
\n" ); document.write( "Collect like terms
\n" ); document.write( "2x^2 + 2x + 1 - 13 = 0
\n" ); document.write( "2x^2 + 2x - 12 = 0
\n" ); document.write( "Divide throughout by 2
\n" ); document.write( "2(x^2 + x - 6)= 0
\n" ); document.write( "2(x + 3)(x - 2) = 0
\n" ); document.write( "x + 3 = 0
\n" ); document.write( "x = -3
\n" ); document.write( "x - 2 = 0
\n" ); document.write( "x = 2
\n" ); document.write( "Substitute x = -3 and 2
\n" ); document.write( "into the equation y = x + 1
\n" ); document.write( "to get the y coordinates.
\n" ); document.write( "x = -3
\n" ); document.write( "y = x + 1
\n" ); document.write( "y = -3 + 1
\n" ); document.write( "y = -2
\n" ); document.write( "x = 2
\n" ); document.write( "y = x + 1
\n" ); document.write( "y = 2 + 1
\n" ); document.write( "y = 3
\n" ); document.write( "Points of intersection are:
\n" ); document.write( "(-3,-2) and (2,3)
\n" ); document.write( "Hope this helps :-)
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