document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003747>Question 1003747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose length is 2 cm more than twice its width and which has a diagonal of 13 c </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620408 by </B><A HREF=/tutors/aboutme.mpl?userid=parassingh><B>parassingh(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=parassingh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length be l and the width be b.<BR>\n" );
document.write( "Now, l= 2b +2 is given.\r<BR>\n" );
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document.write( "According to pythagoras theorem<BR>\n" );
document.write( "(diagonal)^2= l^2 + b^2<BR>\n" );
document.write( "so, 13*13= l*l + b*b;<BR>\n" );
document.write( " 169= (2b+2)(2b+2) + b*b;<BR>\n" );
document.write( " 169= 4(b+1)(b+1) + b^2;<BR>\n" );
document.write( " 169= 4(b^2 + 2b + 1) + b^2;<BR>\n" );
document.write( " 169= 5b^2 + 8b + 4;<BR>\n" );
document.write( " 5b^2 + 8b - 165 = 0;<BR>\n" );
document.write( " 5b^2 + 33b - 25b -165 =0;<BR>\n" );
document.write( " b(5b +33) - 5(5b + 33) = 0;<BR>\n" );
document.write( " (b - 5)*(5b + 33) = 0;<BR>\n" );
document.write( "  so, b=5;<BR>\n" );
document.write( " l= 2b+2 = 10+2= 12;\r<BR>\n" );
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document.write( "so, l=12, b=5;  </SPAN>\n" );
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