document.write( "Question 1003712: Melissa walks 3 miles to the house of a friend and returns home on a bike. She averages 4 miles per hour faster when cycling than when walking, and the total time for both trips is two hours. Find her walking speed. \n" ); document.write( "
Algebra.Com's Answer #620355 by mananth(16946)\"\" \"About 
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Melissa walks 3 miles to the house of a friend and returns home on a bike. She averages 4 miles per hour faster when cycling than when walking, and the total time for both trips is two hours. Find her walking speed.\r
\n" ); document.write( "\n" ); document.write( "Melissa walks 3 miles to the house of a friend and returns home on a bike.
\n" ); document.write( "let the speed be x
\n" ); document.write( "she takes 3/x hours to reach\r
\n" ); document.write( "\n" ); document.write( " She averages 4 miles per hour faster when cycling than when walking,
\n" ); document.write( "speed = (x+4)\r
\n" ); document.write( "\n" ); document.write( "time taken = 3/(x+4)\r
\n" ); document.write( "\n" ); document.write( " and the total time for both trips is two hours.
\n" ); document.write( "3/x + 3/(x+4) = 2\r
\n" ); document.write( "\n" ); document.write( "multiply the equation by x(x+4)\r
\n" ); document.write( "\n" ); document.write( "3(x+4)+3x = 2x(x+4)\r
\n" ); document.write( "\n" ); document.write( "3x+4+3x = 2x^2+8x\r
\n" ); document.write( "\n" ); document.write( "2x^2+2x-4=0
\n" ); document.write( "/2
\n" ); document.write( "x^2+x-2=0\r
\n" ); document.write( "\n" ); document.write( "x^2-2x+x-2=0\r
\n" ); document.write( "\n" ); document.write( "x(x-2)+1(x-2)=0\r
\n" ); document.write( "\n" ); document.write( "(x-2)(x+1)=0\r
\n" ); document.write( "\n" ); document.write( "x=2 OR -1\r
\n" ); document.write( "\n" ); document.write( "ignore negative\r
\n" ); document.write( "\n" ); document.write( "x=2\r
\n" ); document.write( "
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\n" ); document.write( "\n" ); document.write( "her walking speed.= 2mph
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