document.write( "Question 1003708: the lenght of a kitchen floor is 3ft more than the width.the area is 100 sq ft. what are the length and width of the kitchen to the nearest hundredth of a foot \n" ); document.write( "

Algebra.Com's Answer #620348 by mananth(16946) $\"\"$ $\"About$

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let length be x
\n" ); document.write( "width = (x-3)\r
\n" ); document.write( "\n" ); document.write( "Area = L*w\r
\n" ); document.write( "\n" ); document.write( "x(x-3) = 100\r
\n" ); document.write( "\n" ); document.write( "x^2-3x =100
\n" ); document.write( "x^2-3x=100\r
\n" ); document.write( "\n" ); document.write( "x^2-3x +(9/4) = 100+9/4\r
\n" ); document.write( "\n" ); document.write( "(x-(3/2))^2 = 409/4\r
\n" ); document.write( "\n" ); document.write( " $\"x-%283%2F2%29\"$ = +/- $\"sqrt%28409%29%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( "x= 3/2 + $\"sqrt%28409%29%2F2\"$ OR x = (3/2) - $\"sqrt%28409%29%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( "ignore negative value\r
\n" ); document.write( "\n" ); document.write( "x= 11.61 => ;length\r
\n" ); document.write( "\n" ); document.write( "y = 8.611 => width\r
\n" ); document.write( "\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "11.61*8.61 = 99.96 sq ft\r
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