document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003623>Question 1003623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the tangent line to the graph of f(x)=(x^3+1)/(x^2+x+1)<BR>\n" );
document.write( "at the point whose x-coordinate is 1<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620338 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use quotient rule to find f'(x).\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large f'(x) = \frac{3x^2(x^2 + x + 1) - (x^3 + 1)(2x + 1)}{(x^2 + x + 1)^2\">\r<BR>\n" );
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document.write( "Substitute x = 1 to compute f'(1), that is, the slope of the tangent line at x = 1.\r<BR>\n" );
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document.write( "You also know f(1) = 2/3, so you can then express the equation of the tangent line in the form <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large y - y_1 = m(x - x_1)\">. </SPAN>\n" );
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