document.write( "Question 1003589: Isha is 5 years younger than her brother. After 4 years their ages will be in ratio 2:3. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #620332 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Isha is 5 years younger than her brother. \n" ); document.write( "i = b - 5 \n" ); document.write( " After 4 years their ages will be in ratio 2:3. \n" ); document.write( " \n" ); document.write( "replace i with (b-5) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "3(b-1) = 2(b+4) \n" ); document.write( "3b - 3 = 2b + 8 \n" ); document.write( "3b - 2b = 8 + 3 \n" ); document.write( "b = 11 is the brother's age \n" ); document.write( "then \n" ); document.write( "i = 11 - 5 \n" ); document.write( "i = 6 yrs is I's age \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Add 4 to each age and check to see the ratio \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |