document.write( "Question 1003589: Isha is 5 years younger than her brother. After 4 years their ages will be in ratio 2:3. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #620332 by ankor@dixie-net.com(22740)\"\" \"About 
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Isha is 5 years younger than her brother.
\n" ); document.write( "i = b - 5
\n" ); document.write( " After 4 years their ages will be in ratio 2:3.
\n" ); document.write( "\"%28%28i%2B4%29%29%2F%28%28b%2B4%29%29\" = \"2%2F3\"
\n" ); document.write( "replace i with (b-5)
\n" ); document.write( "\"%28%28b-5%29%2B4%29%2F%28%28b%2B4%29%29\" = \"2%2F3\"
\n" ); document.write( "\"%28%28b-1%29%29%2F%28%28b%2B4%29%29\" = \"2%2F3\"
\n" ); document.write( "cross multiply
\n" ); document.write( "3(b-1) = 2(b+4)
\n" ); document.write( "3b - 3 = 2b + 8
\n" ); document.write( "3b - 2b = 8 + 3
\n" ); document.write( "b = 11 is the brother's age
\n" ); document.write( "then
\n" ); document.write( "i = 11 - 5
\n" ); document.write( "i = 6 yrs is I's age
\n" ); document.write( "
\n" ); document.write( ":
\n" ); document.write( "Add 4 to each age and check to see the ratio
\n" ); document.write( "\"10%2F15\" = \"2%2F3\"\r
\n" ); document.write( "\n" ); document.write( ":
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