document.write( "Question 1003673: The product of two consecutive positive integers is 119 more than the next integers. What is the largest of the three integers?
\n" ); document.write( "11
\n" ); document.write( "13
\n" ); document.write( "14
\n" ); document.write( "9 \n" ); document.write( "

Algebra.Com's Answer #620322 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "let the three consecutive positive integers be $\"x\"$ , $\"x%2B1\"$ ,and $\"x%2B2\"$ \r
\n" ); document.write( "\n" ); document.write( "if the product of two consecutive positive integers is $\"119\"$ more than the next integer, we have \r
\n" ); document.write( "\n" ); document.write( " $\"x%28x%2B1%29=%28x%2B2%29%2B119\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2Bx=x%2B121\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2Bx-x=121\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2=121\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=sqrt%28121%29\"$ ........since given that integers are positive\r
\n" ); document.write( "\n" ); document.write( "solution we need is: $\"x=11\"$ \r
\n" ); document.write( "\n" ); document.write( "so,
\n" ); document.write( "first integer is: $\"11\"$
\n" ); document.write( "second integer is: $\"12\"$
\n" ); document.write( "third integer is: $\"13\"$ =>the largest of the three integers\r
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