document.write( "Question 1003638: Find three consecutive odd integers such that three times the first minus the second is one more than the third \n" ); document.write( "

Algebra.Com's Answer #620303 by josgarithmetic(39617) $\"\"$ $\"About$

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Before finding them, 2n+1, 2n+3, 2n+5.\r
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\n" ); document.write( "\n" ); document.write( "The description means $\"3%282n%2B1%29-%282n%2B3%29=1%2B%282n%2B5%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Solve for n and evaluate the three consecutive odd integers.\r
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\n" ); document.write( "\n" ); document.write( " $\"6n%2B3-2n-3=1%2B2n%2B5\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"6n-2n=2n%2B5%2B1\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"4n-2n=6\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"2n=6\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%28n=3%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "The integers are 7, 9, 11. \n" ); document.write( "

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