document.write( "Question 1003538: A random sample of 100 observations from a population with standard deviation 28.51 yielded a sample mean of 94.9.\r
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document.write( "1. Given that the null hypothesis is μ=90 and the alternative hypothesis is μ>90 using α=.05, find the following:
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document.write( "(a) Test statistic =
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document.write( "(b) P - value: \r
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document.write( "2. Given that the null hypothesis is μ=90 and the alternative hypothesis is μ≠90 using α=.05, find the following:
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document.write( "(a) Test statistic =
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document.write( "(b) P - value \n" );
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Algebra.Com's Answer #620234 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A random sample of 100 observations from a population with standard deviation 28.51 yielded a sample mean of 94.9. \n" ); document.write( "1. Given that the null hypothesis is μ=90 \n" ); document.write( "and the alternative hypothesis is μ>90 using α=.05, find the following: \n" ); document.write( "(a) Test statistic:: \n" ); document.write( "z(94.9) = (94.9-90)/(28.51/sqrt(100) = 1.7190. \n" ); document.write( "------ \n" ); document.write( "(b) P - value:: \n" ); document.write( "P-value = P(z > 1.719 ) = normalcdf(1.719,100) = 0.0428 \n" ); document.write( "---------------------- \n" ); document.write( "2. Given that the null hypothesis is μ=90 and the alternative hypothesis is μ≠90 using α=.05, find the following: \n" ); document.write( "(a) Test statistic:: \n" ); document.write( "z(94.9) = 1.719 \n" ); document.write( "---------------- \n" ); document.write( "(b) P - value:: \n" ); document.write( "p-value = 2*P(z > 1.719) = 0.0856 \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |