document.write( "Question 85822: This should be an easy question, I'm just stumped.\r
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document.write( "Write down the nth term of the sequence suggested by the pattern 1, 1/2, 3, 1/4, 5, 1/6, 7, 1/8,...\r
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document.write( "Any help would be nice. \n" );
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Algebra.Com's Answer #62022 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Call \"n\" the number of the term in the sequence. Then you can write: \n" ); document.write( ". \n" ); document.write( "When n = 1 the term is 1 \n" ); document.write( "When n = 2 the term is \n" ); document.write( "When n = 3 the term is 3 \n" ); document.write( "When n = 4 the term is \n" ); document.write( "When n = 5 the term is 5 \n" ); document.write( "When n = 6 the term is \n" ); document.write( "When n = 7 the term is 7 \n" ); document.write( "When n = 8 the term is \n" ); document.write( ". \n" ); document.write( "And you can extend this sequence using the following two rules: \n" ); document.write( ". \n" ); document.write( "If n = odd, the term is n and \n" ); document.write( "If n = even, the term is \n" ); document.write( ". \n" ); document.write( "So for the 100th term (n = 100, an even number) the term in the sequence should be \n" ); document.write( "and for the \n" ); document.write( "101st term (n = 101, an odd number) the term in the sequence should be 101. \n" ); document.write( ". \n" ); document.write( "Hope this works for you. \n" ); document.write( " \n" ); document.write( " |