document.write( "Question 85822: This should be an easy question, I'm just stumped.\r
\n" ); document.write( "\n" ); document.write( "Write down the nth term of the sequence suggested by the pattern 1, 1/2, 3, 1/4, 5, 1/6, 7, 1/8,...\r
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Algebra.Com's Answer #62022 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Call \"n\" the number of the term in the sequence. Then you can write:
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\n" ); document.write( "When n = 1 the term is 1
\n" ); document.write( "When n = 2 the term is \"1%2F2\"
\n" ); document.write( "When n = 3 the term is 3
\n" ); document.write( "When n = 4 the term is \"1%2F4\"
\n" ); document.write( "When n = 5 the term is 5
\n" ); document.write( "When n = 6 the term is \"1%2F6\"
\n" ); document.write( "When n = 7 the term is 7
\n" ); document.write( "When n = 8 the term is \"1%2F8\"
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\n" ); document.write( "And you can extend this sequence using the following two rules:
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\n" ); document.write( "If n = odd, the term is n and
\n" ); document.write( "If n = even, the term is \"1%2Fn\"
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\n" ); document.write( "So for the 100th term (n = 100, an even number) the term in the sequence should be \"1%2F100\"
\n" ); document.write( "and for the
\n" ); document.write( "101st term (n = 101, an odd number) the term in the sequence should be 101.
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\n" ); document.write( "Hope this works for you.
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