document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003516>Question 1003516</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes Mohammed 30 mins to get to work, and 50 minutes to return. He goes 6mph slower on the return. Find out how far she has to travel. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620199 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call his rate going to work, x.<BR>\n" );
document.write( "Then his rate coming home is x - 6.<BR>\n" );
document.write( "Expressing the times in hours, and using rt=d, we get<BR>\n" );
document.write( "(1/2)x = (5/6)(x - 6)<BR>\n" );
document.write( "Multiply by six to clear fractions...<BR>\n" );
document.write( "3x = 5(x - 6)<BR>\n" );
document.write( "3x = 5x - 30<BR>\n" );
document.write( "-2x = -30<BR>\n" );
document.write( "x = 15 mph<BR>\n" );
document.write( "x-6 = 9mph<BR>\n" );
document.write( "The distance to work is (1/2)(15) = 7.5 miles </SPAN>\n" );
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