document.write( "Question 1003485: Solve on interval [0,360]
\n" ); document.write( "2cos^2x=1
\n" ); document.write( "3cot^2x=1
\n" ); document.write( "Csc^2x-cscx \n" ); document.write( "

Algebra.Com's Answer #620180 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( " $\"2cos%5E2%28x%29\"$ = $\"1\"$ ,\r
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\n" ); document.write( "\n" ); document.write( " $\"cos%5E2%28x%29\"$ = $\"1%2F2\"$ ,\r
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\n" ); document.write( "\n" ); document.write( " $\"cos%28c%29\"$ = +/- $\"sqrt%282%29%2F2\"$ ,\r
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\n" ); document.write( "\n" ); document.write( " $\"cos%28x%29\"$ = $\"sqrt%282%29%2F2\"$ -----> x = 45°, 315°\r
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\n" ); document.write( "\n" ); document.write( " $\"cos%28x%29\"$ = $\"-sqrt%282%29%2F2\"$ -----> x = 135°, 225°.\r
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\n" ); document.write( "\n" ); document.write( "Answer. 45°, 135°, 225°, 315°.\r
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