document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003398>Question 1003398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of the four geometric means between 160 and 5. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620157 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since there are four means, there are five  multiplicative steps going from 160 to 5...another way of showing that is...<BR>\n" );
document.write( "160r^5 = 5<BR>\n" );
document.write( "r^5 = 5/160 = 1/32<BR>\n" );
document.write( "r = 1/2<BR>\n" );
document.write( "Thus the terms must be<BR>\n" );
document.write( "160,80,40,20,10,5<BR>\n" );
document.write( "and the sum of the four intermediate means is<BR>\n" );
document.write( "150 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );