document.write( "Question 1003408: A model rocket is launched with an initial velocity of 180 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given by
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document.write( "h = −16t2 + 180t.
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document.write( " How many seconds after launch will the rocket be 410 ft above the ground? Round to the nearest hundredth of a second. \n" );
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Algebra.Com's Answer #620121 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! h(t) = -16t^2 + 180t = 410 \n" ); document.write( "Solve for t \n" ); document.write( " \n" ); document.write( " |