document.write( "Question 1003361: If 1 is a zero of p(x) =ax^3-(a-1)x-1 then find value of a \n" ); document.write( "
Algebra.Com's Answer #620089 by mananth(16946)\"\" \"About 
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\n" ); document.write( "p(x) =ax^3-(a-1)x-1\r
\n" ); document.write( "\n" ); document.write( "since 1 is the root\r
\n" ); document.write( "\n" ); document.write( "p(1) = a(1)^3-(1-1)x -1\r
\n" ); document.write( "\n" ); document.write( "=a-1\r
\n" ); document.write( "\n" ); document.write( "by remainder theorem\r
\n" ); document.write( "\n" ); document.write( "a-1 = 0
\n" ); document.write( "therefore a=1
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