document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003346>Question 1003346</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x) = 2x^2 + 3x + 1\r<BR>\n" );
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document.write( "find the minimum value of the function </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620071 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  f(x) = 2x^2 + 3x + 1 <BR>\n" );
document.write( "find the minimum value of the function <BR>\n" );
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document.write( "min occurs at x = -b/(2a) = -3/(4) = -3/4<BR>\n" );
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document.write( "min value = f(-3/4) = 2(9/16) + 3(-3/4) + 1 = (18/16) -(36/16) + 16/16 = -1/8<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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