document.write( "Question 1003338: Max and Rebecca's are in cars 120 miles apart. Both Drivers are going at a constant speed of 30/mph and 40/mph respectively. How far apart will the 2 cars be in exactly 1 hour before they meet. \n" ); document.write( "
Algebra.Com's Answer #620065 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Max and Rebecca's are in cars 120 miles apart. Both Drivers are going at a constant speed of 30/mph and 40/mph respectively. How far apart will the 2 cars be in exactly 1 hour before they meet. \n" ); document.write( "------- \n" ); document.write( "Max DATA: \n" ); document.write( "rate = 30 mph ; distance = x miles ; time = x/30 hrs \n" ); document.write( "---------- \n" ); document.write( "Rebecca DATA: \n" ); document.write( "rate = 40 mph ; distance = 120-x miles ; time = (120-x)/40 hrs \n" ); document.write( "------ \n" ); document.write( "Equation to find out when then would meet:: \n" ); document.write( "x/30 = (120-x)/40 \n" ); document.write( "--- \n" ); document.write( "40x = 30*120 - 30x \n" ); document.write( "70x = 30*120 \n" ); document.write( "x = 3600/70 = 51.42 miles \n" ); document.write( "--- \n" ); document.write( "time for the cars to meet 51.42/30 = 1.714 hrs \n" ); document.write( "----- \n" ); document.write( "How far apart will the 2 cars be in exactly 1 hour before they meet. \n" ); document.write( "Max will have gone 0.714*30 = 21.42 miles \n" ); document.write( "Rebecca will have gone 0.714*40 = 28.56 miles \n" ); document.write( "----- \n" ); document.write( "Ans: 28.56-21.42 = 7.14 miles apart \n" ); document.write( "---------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |