document.write( "Question 1003308: The second of three numbers is eight more than the first and third number is three less than three times the first number.
\n" ); document.write( "If the third number is 15 more than the second, find the three numbers. \r
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\n" ); document.write( "\n" ); document.write( "I tried it by making the equation: x+x+8+3x-3=x-7
\n" ); document.write( "But it didn't work
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Algebra.Com's Answer #620046 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "First number = \"x\"
\n" ); document.write( "Second number = \"x+%2B+8\"
\n" ); document.write( "Third number = \"3x+-+3\"
\n" ); document.write( "Our equation is: \"3x+-+3+=+%28x+%2B+8%29+%2B+15\"\r
\n" ); document.write( "\n" ); document.write( "Solving for \"x\" we get
\n" ); document.write( "\"3x+-+3+=+x+%2B+23\"
\n" ); document.write( "\"3x+-+x+=+3+%2B+23\"
\n" ); document.write( "\"2x+=+26\"
\n" ); document.write( "\"x+=+13\"\r
\n" ); document.write( "\n" ); document.write( "So, the first number is \"13\".
\n" ); document.write( "The second number is \"13%2B8=21\".
\n" ); document.write( "The third number is \"3%2A13-3=36\".
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