document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003160>Question 1003160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The price per unit, p and the demand x, for a particular material are related by the linear equation p=40-2/5x, while the supply is given by the linear equation p= 2/5x. At what value of p does supply equal demand?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620017 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From p=40-2/5x and p= 2/5x we can set them equal and get<BR>\n" );
document.write( "40 - (2/5)x = (2/5)x<BR>\n" );
document.write( "40 = (4/5)x<BR>\n" );
document.write( "x = 50<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "p = (2/5)x = (2/5)(50) = 20 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );