document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003232>Question 1003232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tom's and Tim's ages add up to 21 years. In 3 years, Tom will be twice Tim’s age. How old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620002 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call Tom and Tim's age NOW, x and y.<BR>\n" );
document.write( "Thus<BR>\n" );
document.write( "x + y = 21<BR>\n" );
document.write( "In 3 years,<BR>\n" );
document.write( "x+3 = 2(y+3) = 2y + 6<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = 2y + 3<BR>\n" );
document.write( "Now substitute that into the first equation and get<BR>\n" );
document.write( "2y + 3 + y = 21<BR>\n" );
document.write( "3y = 18<BR>\n" );
document.write( "y = 6<BR>\n" );
document.write( "x = 15 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );