document.write( "Question 1003202: Hello, I am working on a series of questions with the equation y-3=3(x+1). I have the slope-intercept form y=3x+6, and the standard form 3x-y=-6? Now, I am trying to find an equation in standard form of a perpendicular line that passes through (5,-1). I took y=mx+b and solved for b=2/3, then y=-1/3x+2/3 and switched it around to y+x/3=2/3. Is this correct? I am confused because standard form is Ax+By=c, if my answer should be x/3+y=2/3?? Seems like that would be in the correct form. Thank you for your time! \n" ); document.write( "
Algebra.Com's Answer #619980 by Alan3354(69443)\"\" \"About 
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I have the slope-intercept form y=3x+6, and the standard form 3x-y=-6?
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\n" ); document.write( "Now, I am trying to find an equation in standard form of a perpendicular line that passes through (5,-1).
\n" ); document.write( "I took y=mx+b and solved for b=2/3, then y=-1/3x+2/3 and switched it around to y+x/3=2/3. Is this correct?
\n" ); document.write( "It's correct, tho you didn't show how you got it.
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\n" ); document.write( "The slope is m = -1/3
\n" ); document.write( "Use y-y1 = m*(x-x1) where (x1,y1) is the point (5,-1)
\n" ); document.write( "y+1 = (-1/3)*(x-5)
\n" ); document.write( "3y+3 = -x+5
\n" ); document.write( "x + 3y = 2
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\n" ); document.write( "I am confused because standard form is Ax+By=c, if my answer should be x/3+y=2/3?? Seems like that would be in the correct form.
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\n" ); document.write( "x/3+y=2/3
\n" ); document.write( "Standard form has integers for A, B & C
\n" ); document.write( "Multiply by 3
\n" ); document.write( "x + 3y = 2\r
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