document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003095>Question 1003095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if AB is 4 cm longer than BC and the perimeter of ABCD is 68 cm, find the measures of AB,BC,CD and AD </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619941 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "I am assuming this is a rectangle.<BR>\n" );
document.write( "Make the width = 'x' (BC)<BR>\n" );
document.write( "Length = 4 + x (AB)<BR>\n" );
document.write( "Perimeter of a rectangle =<BR>\n" );
document.write( "2 x Width + 2 x Length<BR>\n" );
document.write( "68 = 2(x) + 2(4 + x)<BR>\n" );
document.write( "68 = 2x + 8 + 2x<BR>\n" );
document.write( "Collect like terms<BR>\n" );
document.write( "2x + 2x = 68 - 8<BR>\n" );
document.write( "4x = 60<BR>\n" );
document.write( "x = 15<BR>\n" );
document.write( "AB = CD = 19 cm<BR>\n" );
document.write( "BC = AD = 15 cm<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );