document.write( "Question 1003100: A total of $12,000 is invested in two accounts. The interest rate on one account is 9%; on the second account, the interest rte is 6%. How much should be invested in each account so that both accounts earn the same amount of annual interest? \n" ); document.write( "
Algebra.Com's Answer #619898 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Part I 9.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 6.00% per annum ------------ Amount invested = y =
\n" ); document.write( " 12000
\n" ); document.write( "Interest----- equal
\n" ); document.write( "
\n" ); document.write( "Part I 9.00% per annum ---x
\n" ); document.write( "Part II 6.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + y= 12000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "9.00% x = 6.00%
\n" ); document.write( "9x=6y
\n" ); document.write( "x= 2/3 y\r
\n" ); document.write( "\n" ); document.write( "plug in (1)\r
\n" ); document.write( "\n" ); document.write( "(2/3) y + y =12000\r
\n" ); document.write( "\n" ); document.write( "(2y+3y) /3 = 12000\r
\n" ); document.write( "\n" ); document.write( "5y = 36000\r
\n" ); document.write( "\n" ); document.write( "y = 7200\r
\n" ); document.write( "\n" ); document.write( "x = 4800
\n" ); document.write( " \n" ); document.write( "
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