document.write( "Question 1003078: The length of the top of the table is 2 m greater than the width. The area is 80m^2. Find the dinensions of the table.
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Algebra.Com's Answer #619885 by mananth(16946)\"\" \"About 
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Area = 80 sq. ft
\n" ); document.write( "Length = x ft
\n" ); document.write( "Width ( x -2 )
\n" ); document.write( "Area = x * ( x -2 )
\n" ); document.write( "80 = x^2 + -2 x
\n" ); document.write( "x^2 -2 x -80 = 0\r
\n" ); document.write( "\n" ); document.write( "x^2-10x+8x-80=0\r
\n" ); document.write( "\n" ); document.write( "x(x-10)+8(x-10)=0\r
\n" ); document.write( "\n" ); document.write( "(x-10)(x+8)=0\r
\n" ); document.write( "\n" ); document.write( "x= 10 ignoring negative\r
\n" ); document.write( "\n" ); document.write( "dimensions are 10 & 8 ft
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