document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003061>Question 1003061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For what value of a are the graphs of 6y=-2x+4 and 2y=ax-5perpendecular<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619874 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619874\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6y=-2x+4 and 2y=ax-5perpendecular\r<BR>\n" );
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document.write( "6y=-2x+4 \r<BR>\n" );
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document.write( "y=-2/6 x +2/3\r<BR>\n" );
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document.write( "y = (-1/3)x +2/3   slope = (-1/3)\r<BR>\n" );
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document.write( " 2y=ax-5\r<BR>\n" );
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document.write( "y= (a/2)x -5/2    slope = (a/2)\r<BR>\n" );
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document.write( "For them to be perpendicular\r<BR>\n" );
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document.write( "(-1/3) = a/2\r<BR>\n" );
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document.write( "a= -2/3\r<BR>\n" );
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