document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002889>Question 1002889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 12 men complete the 2400 square meter ploughing work in 10 days. how many men are required to complete 3600 square meter ploughing work in 18 days?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619849 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12 men complete the 2400 square meter ploughing work in 10 days. how many men are required to complete 3600 square meter ploughing work in 18 days?<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "2400 sq m takes 12*10 = 120 man-days<BR>\n" );
document.write( "--> 1 man-day = 20 sq meters<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "3600/20 = 180 man-days<BR>\n" );
document.write( "180 man-days/18 days = 10 men<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );