document.write( "Question 1002917: zeros of -3,1, and 4;f(2)=30\r
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\n" ); document.write( "\n" ); document.write( "a=-3 b=1 c=4
\n" ); document.write( "f(x)=(x+3)(x-1)(x-4)
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Algebra.Com's Answer #619835 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "zeros of -3,1, and 4;f(2)=30\r
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\n" ); document.write( "\n" ); document.write( "a=-3 b=1 c=4
\n" ); document.write( "f(x)=(x+3)(x-1)(x-4)
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\n" ); document.write( "\n" ); document.write( "f(2) = (2+3)*(2-1)*(2-4) = 5*1*(-2) = -10.\r
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\n" ); document.write( "\n" ); document.write( "So, apply the factor (-3) to f(x):\r
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\n" ); document.write( "\n" ); document.write( "F(x) = -3*f(x).\r
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