document.write( "Question 85751: 2x^4 - 8x^2 + 6 divided by 2x + 2 \n" ); document.write( "
Algebra.Com's Answer #61981 by jim_thompson5910(35256)\"\" \"About 
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Start with the given polynomial \"%282x%5E4+-+8x%5E2+%2B+6%29%2F%282x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "First lets find our test zero:\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B2=0\" Set the denominator \"2x%2B2\" equal to zero\r
\n" ); document.write( "\n" ); document.write( "\"x=-1\" Solve for x.\r
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\n" ); document.write( "\n" ); document.write( "so our test zero is -1\r
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\n" ); document.write( "\n" ); document.write( "Now set up the synthetic division table by placing the test zero in the upperleft corner and placing the coefficients of the numerator to the right of the test zero.(note: remember if a polynomial goes from \"2x%5E4\" to \"-8x%5E2\" there is a zero coefficient for \"x%5E3\". This is simply because \"2x%5E4+-+8x%5E2+%2B+6\" really looks like \"2x%5E4%2B0x%5E3%2B-8x%5E2%2B0x%5E1%2B6x%5E0\"\n" ); document.write( "\n" ); document.write( "
-1|20-806
\r
\n" ); document.write( "\n" ); document.write( "Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 2)\r
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-1|20-806
2
\r
\n" ); document.write( "\n" ); document.write( " Multiply -1 by 2 and place the product (which is -2) right underneath 0\r
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-1|20-806
-2
2
\r
\n" ); document.write( "\n" ); document.write( " Add -2 and 0 to get -2. Place the sum right underneath -2.\r
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-1|20-806
-2
2-2
\r
\n" ); document.write( "\n" ); document.write( " Multiply -1 by -2 and place the product (which is 2) right underneath -8\r
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-1|20-806
-22
2-2
\r
\n" ); document.write( "\n" ); document.write( " Add 2 and -8 to get -6. Place the sum right underneath 2.\r
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-1|20-806
-22
2-2-6
\r
\n" ); document.write( "\n" ); document.write( " Multiply -1 by -6 and place the product (which is 6) right underneath 0\r
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-1|20-806
-226
2-2-6
\r
\n" ); document.write( "\n" ); document.write( " Add 6 and 0 to get 6. Place the sum right underneath 6.\r
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-1|20-806
-226
2-2-66
\r
\n" ); document.write( "\n" ); document.write( " Multiply -1 by 6 and place the product (which is -6) right underneath 6\r
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-1|20-806
-226-6
2-2-66
\r
\n" ); document.write( "\n" ); document.write( " Add -6 and 6 to get 0. Place the sum right underneath -6.\r
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-1|20-806
-226-6
2-2-660
\r
\n" ); document.write( "\n" ); document.write( "Since the last column adds to zero, we have a remainder of zero. This means \"2x%2B2\" is a factor of \"2x%5E4+-+8x%5E2+%2B+6\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets look at the bottom row of coefficients:\r
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\n" ); document.write( "\n" ); document.write( "The first 4 coefficients (2,-2,-6,6) form the quotient\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E3+-+2x%5E2+-+6x+%2B+6\"\r
\n" ); document.write( "\n" ); document.write( "Notice in the denominator \"2x%2B2\", the x term has a coefficient of 2, so we need to divide the quotient by 2 like this:\r
\n" ); document.write( "\n" ); document.write( "\"%282x%5E3+-+2x%5E2+-+6x+%2B+6%29%2F2=x%5E3+-+x%5E2+-+3x+%2B+3\"\r
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\n" ); document.write( "\n" ); document.write( "So \"%282x%5E4+-+8x%5E2+%2B+6%29%2F%282x%2B2%29=x%5E3+-+x%5E2+-+3x+%2B+3\"
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