document.write( "Question 12234: OK , here is the problem, solve for x.
\n" ); document.write( "x^(1+ln x)= 7,39
\n" ); document.write( "Doesnīt look that complicated but I keep getting stuck.
\n" ); document.write( "Incidentally Iīve discovered that 7,39 = e^2 and I think that the answer for x = square root of 7,39, but donīt know how to get there.
\n" ); document.write( "Thanks in advance for any assistance.
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Algebra.Com's Answer #6198 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E%281%2Blnx%29+=+7.39\"\r
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\n" ); document.write( "\n" ); document.write( "OK, take logs
\n" ); document.write( "\"%281%2Blnx%29lnx+=+ln%287.39%29\"
\n" ); document.write( "\"lnx+%2B+%28lnx%29%5E2+=+2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28lnx%29%5E2+%2B+lnx+-2+=+0\"
\n" ); document.write( "OK, this is a quadratic, so letting y=lnx, we have \"y%5E2+%2B+y+-+2+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "This factorises to (y+2)(y-1) = 0, so that \r
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\n" ); document.write( "\n" ); document.write( "y+2 = 0 OR y-1 = 0\r
\n" ); document.write( "\n" ); document.write( "--> y = -2 or y = 1\r
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\n" ); document.write( "\n" ); document.write( "Hence
\n" ); document.write( "lnx = -2 OR lnx = 1\r
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\n" ); document.write( "\n" ); document.write( "-->
\n" ); document.write( "\"x+=+e%5E%28-2%29\" or x = e\r
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\n" ); document.write( "\n" ); document.write( "jon.
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