document.write( "Question 85761: An investor placed a total of $16,000 in two simple interest accounts. One account earned a simple interest rate of 5.9%, and the other earned a simple interest rate of 3.6%. The two accounts earned a total of $668. How much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #61977 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .059X+.036(16000-X)=668 \n" ); document.write( ".059X+576-.036X=668 \n" ); document.write( ".023X=668-576 \n" ); document.write( ".023X=92 \n" ); document.write( "X=92/.023 \n" ); document.write( "X=4000 AMOUNT INVESTED @ 5.9% \n" ); document.write( "16000-4000=12000 INVESTED @ 3.6%. \n" ); document.write( "PROOF \n" ); document.write( ".059*4000+.036*12000=668 \n" ); document.write( "236+432=668 \n" ); document.write( "668=668 \n" ); document.write( " |