document.write( "Question 85761: An investor placed a total of $16,000 in two simple interest accounts. One account earned a simple interest rate of 5.9%, and the other earned a simple interest rate of 3.6%. The two accounts earned a total of $668. How much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #61977 by checkley75(3666)\"\" \"About 
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.059X+.036(16000-X)=668
\n" ); document.write( ".059X+576-.036X=668
\n" ); document.write( ".023X=668-576
\n" ); document.write( ".023X=92
\n" ); document.write( "X=92/.023
\n" ); document.write( "X=4000 AMOUNT INVESTED @ 5.9%
\n" ); document.write( "16000-4000=12000 INVESTED @ 3.6%.
\n" ); document.write( "PROOF
\n" ); document.write( ".059*4000+.036*12000=668
\n" ); document.write( "236+432=668
\n" ); document.write( "668=668
\n" ); document.write( "
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