document.write( "Question 85753: Dividing Polynomials: synthetic\r
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\n" ); document.write( "\n" ); document.write( "2x^4 - 10x^2 + 6x - 8 divided by x + 3\r
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Algebra.Com's Answer #61974 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Start with the given polynomial \"%282x%5E4+-+10x%5E2+%2B+6x+-+8%29%2F%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "First lets find our test zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3=0\" Set the denominator \"x%2B3\" equal to zero\r
\n" ); document.write( "\n" ); document.write( "\"x=-3\" Solve for x.\r
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\n" ); document.write( "\n" ); document.write( "so our test zero is -3\r
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\n" ); document.write( "\n" ); document.write( "Now set up the synthetic division table by placing the test zero in the upperleft corner and placing the coefficients of the numerator to the right of the test zero.(note: remember if a polynomial goes from \"2x%5E4\" to \"-10x%5E2\" there is a zero coefficient. This is simply because \"2x%5E4+-+10x%5E2+%2B+6x+-+8\" really looks like \"2x%5E4%2B0x%5E3%2B-10x%5E2%2B6x%5E1%2B-8x%5E0\"\n" ); document.write( "\n" ); document.write( "
-3|20-106-8
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\n" ); document.write( "\n" ); document.write( "Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 2)\r
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-3|20-106-8
2
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\n" ); document.write( "\n" ); document.write( " Multiply -3 by 2 and place the product (which is -6) right underneath 0\r
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-3|20-106-8
-6
2
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\n" ); document.write( "\n" ); document.write( " Add -6 and 0 to get -6. Place the sum right underneath -6.\r
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-3|20-106-8
-6
2-6
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\n" ); document.write( "\n" ); document.write( " Multiply -3 by -6 and place the product (which is 18) right underneath -10\r
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-3|20-106-8
-618
2-6
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\n" ); document.write( "\n" ); document.write( " Add 18 and -10 to get 8. Place the sum right underneath 18.\r
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-3|20-106-8
-618
2-68
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\n" ); document.write( "\n" ); document.write( " Multiply -3 by 8 and place the product (which is -24) right underneath 6\r
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-3|20-106-8
-618-24
2-68
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\n" ); document.write( "\n" ); document.write( " Add -24 and 6 to get -18. Place the sum right underneath -24.\r
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-3|20-106-8
-618-24
2-68-18
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\n" ); document.write( "\n" ); document.write( " Multiply -3 by -18 and place the product (which is 54) right underneath -8\r
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-3|20-106-8
-618-2454
2-68-18
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\n" ); document.write( "\n" ); document.write( " Add 54 and -8 to get 46. Place the sum right underneath 54.\r
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-3|20-106-8
-618-2454
2-68-1846
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\n" ); document.write( "\n" ); document.write( "Since the last column adds to 46, we have a remainder of 46. This means \"x%2B3\" is a not factor of \"2x%5E4+-+10x%5E2+%2B+6x+-+8\"\r
\n" ); document.write( "\n" ); document.write( "Now lets look at the bottom row of coefficients:\r
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\n" ); document.write( "\n" ); document.write( "The first 4 coefficients (2,-6,8,-18) form the quotient\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E3+-+6x%5E2+%2B+8x+-+18\"\r
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\n" ); document.write( "\n" ); document.write( "and the last coefficient 46, is the remainder, which is placed over \"x%2B3\" like this\r
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\n" ); document.write( "\n" ); document.write( "\"46%2F%28x%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "Putting this altogether, we get:\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E3+-+6x%5E2+%2B+8x+-+18%2B46%2F%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \r
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\n" ); document.write( "\n" ); document.write( "which looks like this in remainder form:\r
\n" ); document.write( "\n" ); document.write( "\"%282x%5E4+-+10x%5E2+%2B+6x+-+8%29%2F%28x%2B3%29=2x%5E3+-+6x%5E2+%2B+8x+-+18\" remainder 46
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