document.write( "Question 1002871: Find two numbers given that their sum is 48 and the smaller number is equal to 1/5 of the larger number.
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document.write( "The answer at the back of the book is 40,8. \n" );
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Algebra.Com's Answer #619738 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Find two numbers given that their sum is 48 and the smaller number is equal to 1/5 of the larger number. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let one number be x \n" ); document.write( "other be y (x>y)\r \n" ); document.write( "\n" ); document.write( "x+y =48...................(1)\r \n" ); document.write( "\n" ); document.write( "y= (1/5) x\r \n" ); document.write( "\n" ); document.write( "5y=x\r \n" ); document.write( "\n" ); document.write( "x+y =48\r \n" ); document.write( "\n" ); document.write( "substitute x \n" ); document.write( "5y+y =48 \n" ); document.write( "6y=48 \n" ); document.write( "y =8\r \n" ); document.write( "\n" ); document.write( "Now x+y =48 \n" ); document.write( "x+8=48\r \n" ); document.write( "\n" ); document.write( "x=40\r \n" ); document.write( "\n" ); document.write( "40, 8\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |